I have two color values (from a product attribute) which are necessary for product variations but should be excluded from product filters. Can I remove these 2 color values via PHP in the functions.php? The two values should ONLY be removed from the filters, but not anywhere else. The two values from the color attribute ("Farbe" = color) are "weiß/rot" and "weiß/blau". Product filters: http://wordpress.p585884.webspaceconfig.de/shop/ The HTML: <ul class="woocommerce-widget-layered-nav-list"> <li class="woocommerce-widget-layered-nav-list__item wc-layered-nav-term "><a class="awb-woo-attr" rel="nofollow" href="http://wordpress.p585884.webspaceconfig.de/shop/?filter_farbe=weiss-rot"><span class="awb-woo-attr-wrapper"><span class="avada-color-select"><span style="background-color: #862238"></span></span><span class="awb-woo-attr-name">weiß/rot</span></span><span class="awb-woo-attr-count">(1)</span></a></li> <li class="woocommerce-widget-layered-nav-list__item wc-layered-nav-term "><a class="awb-woo-attr" rel="nofollow" href="http://wordpress.p585884.webspaceconfig.de/shop/?filter_farbe=weiss-blau"><span class="awb-woo-attr-wrapper"><span class="avada-color-select"><span style="background-color: #4d5f74"></span></span><span class="awb-woo-attr-name">weiß/blau</span></span><span class="awb-woo-attr-count">(1)</span></a></li> </ul> Screenshot of "Products / Attributes": This jQuery solution I put together works, but I'd prefer to remove the unnecessary code before the page loads with PHP. $('.woocommerce-widget-layered-nav-list__item .awb-woo-attr-name:contains("weiß/rot")').parents().eq(2).remove(); $('.woocommerce-widget-layered-nav-list__item .awb-woo-attr-name:contains("weiß/blau")').parents().eq(2).remove(); In case a PHP solution is not possible. How can I add these lines together? I've tried a "," in between without success.